(1x^2+4x-13)-(-1x^2+4x-9)=

Solution for (1x^2+4x-13)-(-1x^2+4x-9)= equation:

Simplifying
(1x2 + 4x + -13) + -1(-1x2 + 4x + -9) = 0

Reorder the terms:
(-13 + 4x + 1x2) + -1(-1x2 + 4x + -9) = 0

Remove parenthesis around (-13 + 4x + 1x2)
-13 + 4x + 1x2 + -1(-1x2 + 4x + -9) = 0

Reorder the terms:
-13 + 4x + 1x2 + -1(-9 + 4x + -1x2) = 0
-13 + 4x + 1x2 + (-9 * -1 + 4x * -1 + -1x2 * -1) = 0
-13 + 4x + 1x2 + (9 + -4x + 1x2) = 0

Reorder the terms:
-13 + 9 + 4x + -4x + 1x2 + 1x2 = 0

Combine like terms: -13 + 9 = -4
-4 + 4x + -4x + 1x2 + 1x2 = 0

Combine like terms: 4x + -4x = 0
-4 + 0 + 1x2 + 1x2 = 0
-4 + 1x2 + 1x2 = 0

Combine like terms: 1x2 + 1x2 = 2x2
-4 + 2x2 = 0

Solving
-4 + 2x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 2x2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 2x2 = 0 + 4
2x2 = 0 + 4

Combine like terms: 0 + 4 = 4
2x2 = 4

Divide each side by '2'.
x2 = 2

Simplifying
x2 = 2

Take the square root of each side:
x = {-1.414213562, 1.414213562}